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4.9x^2-50x-525=0
a = 4.9; b = -50; c = -525;
Δ = b2-4ac
Δ = -502-4·4.9·(-525)
Δ = 12790
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-\sqrt{12790}}{2*4.9}=\frac{50-\sqrt{12790}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+\sqrt{12790}}{2*4.9}=\frac{50+\sqrt{12790}}{9.8} $
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